Number of lines of code

I was asked to find out the number of lines of code in our entire module so as to figure out how hard is to maintain it. Here is the source to find out the number of lines in a python project

	#!\usr\bin\env python
	import os
	print 'current working directory : ' + os.getcwd()
	total_lines = 0
	def number_of_lines_in_file( filename ):
	global total_lines
	if filename.endswith(".py"):
	with open(os.path.realpath(filename), 'r') as file_handle:
	lines = sum(1 for _ in file_handle)
	print 'no of lines in ' + filename + ' is %d' %lines
	total_lines = total_lines + lines
	def visit_the_directory( folder ):
	for element in os.listdir(folder):
	if os.path.isdir(os.path.join(folder,element)):
	print element + ' is a directroy'
	dir = os.path.join(folder, element)
	print '------------------------------'
	print 'visiting folder ' + dir
	startingTotalLines = total_lines
	visit_the_directory(dir)
	endingTotalLines = total_lines
	LinesInThisModule = endingTotalLines - startingTotalLines
	print 'total lines in ths module : %d' %LinesInThisModule
	print 'total lines until now: %d' %(total_lines)
	print 'exiting folder ' + dir
	print '------------------------------'
	else:
	file = os.path.join(folder, element)
	number_of_lines_in_file(file)
	visit_the_directory(os.getcwd())
	print 'total lines : %d' %(total_lines)

view raw NumberOfLines.py hosted with ❤ by GitHub

Finding out the system is little endian or big endian system

Here first a value 1 is stored in a int variable. Address of that variable is taken and cast as a char address which will work only on the first byte of the word. If a value one is available in the char then its little endian system otherwise its big endian

	# include <stdio.h>
	# include <conio.h>
	void main()
	{
	int i = 1;
	char *c = (char *) &i;
	if (*c)
	printf("Little endian");
	else
	printf("Big endian");
	getchar();
	}

view raw endian.c hosted with ❤ by GitHub